a=v^2/r=(10pi r/1)^2 / r
a= 100PI^2 r
A point on a wheel rotating at 5revs/s is located 0.20m away from the axis. What is the centripetal acceleration?
a. 198m/s^2
b. .05m/s^2
c. 48m/s^2
d. 1.35m/s^2
1 answer
a. 198m/s^2
b. .05m/s^2
c. 48m/s^2
d. 1.35m/s^2
1 answer