Asked by Andy
A wheel initially rotating at an angular speed of 1.2 rad/s turns through 34 revolutions during the time that it is subject to angular accelaration of .4 rad/s/s. How long did the accelaration last?
So I used theta=Wot+.5at^2. converted rev to rad. and set it up like a quadrtaic equation giving 1.2t+.2t^2-213.6 giving me t equals 13.4 seconds but that is not right??
So I used theta=Wot+.5at^2. converted rev to rad. and set it up like a quadrtaic equation giving 1.2t+.2t^2-213.6 giving me t equals 13.4 seconds but that is not right??
Answers
Answered by
drwls
34 rev = 213.6 rad is OK
(1/2)*0.4 t^2 + 1.2 t -213.6 = 0 is OK
The positive root is
t = [-1.2 + sqrt(1.44 + 170.88)]/0.4 = 29.8 s
You seem to have used the quadratic equation incorrectly.
(1/2)*0.4 t^2 + 1.2 t -213.6 = 0 is OK
The positive root is
t = [-1.2 + sqrt(1.44 + 170.88)]/0.4 = 29.8 s
You seem to have used the quadratic equation incorrectly.
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