angular displacement=avgspeed*time=(1/2)(10+2.5)*30
In rotations, divide by 2PI
A rotating wheel as an initial angular velocity of 10rad/s and 2.5rad/s^2.how many revolution does it will complete in 30seconds?
2 answers
For accelerated motion
2πN = ω(o)t +εt^2/2,
N =t (ω(o) +0.5εt)/2π=
= 30•(10+0.5•2.5•30)/2•3.14 =226.8 rev
2πN = ω(o)t +εt^2/2,
N =t (ω(o) +0.5εt)/2π=
= 30•(10+0.5•2.5•30)/2•3.14 =226.8 rev
3 answers