Asked by minas

A rotating wheel as an initial angular velocity of 10rad/s and 2.5rad/s^2.how many revolution does it will complete in 30seconds?

Answers

Answered by bobpursley
angular displacement=avgspeed*time=(1/2)(10+2.5)*30

In rotations, divide by 2PI
Answered by Elena
For accelerated motion

2πN = ω(o)t +εt^2/2,
N =t (ω(o) +0.5εt)/2π=
= 30•(10+0.5•2.5•30)/2•3.14 =226.8 rev
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