Asked by NELLY
ALuminum can be determined gravimetricaly by the reaction with solution of 8-hydroxyquinoline (C9H7NO3).The net ionic equation . A mass of 0.1248g of Al(C9H6NO)3 WAS obtained by precipitating all of the the Al3+ from a solution prepared by dissolving 1.8571g of a mineral. what is the mass percent of alumininum in the mineral sample
Answers
Answered by
Devron
Now, for every mole of Al(C9H6NO)3, there is 1 mole of Al^3+. i.e., 1 mole of Al=1 mole of Al(C9H6NO)3
Al(C9H6NO)3 *(1 mole/459.4317 g)= moles of Al(C9H6NO)3
moles of Al(C9H6NO)3=moles of Al^3+
moles of Al^3+*(26.98g/1 mole)= mass of Al^3+ in grams
(mass of Al^3+ in grams/1.8571g)*100=mass percent of Al^3+ in the mineral sample
***Answer contains no more and no less than four significant figures.
Al(C9H6NO)3 *(1 mole/459.4317 g)= moles of Al(C9H6NO)3
moles of Al(C9H6NO)3=moles of Al^3+
moles of Al^3+*(26.98g/1 mole)= mass of Al^3+ in grams
(mass of Al^3+ in grams/1.8571g)*100=mass percent of Al^3+ in the mineral sample
***Answer contains no more and no less than four significant figures.
Answered by
Devron
@@Look for correction.
Now, for every mole of Al(C9H6NO)3, there is 1 mole of Al^3+. i.e., 1 mole of Al=1 mole of Al(C9H6NO)3
@@0.1248g of Al(C9H6NO)3 *(1 mole/459.4317 g)= moles of Al(C9H6NO)3
moles of Al(C9H6NO)3=moles of Al^3+
moles of Al^3+*(26.98g/1 mole)= mass of Al^3+ in grams
(mass of Al^3+ in grams/1.8571g)*100=mass percent of Al^3+ in the mineral sample
***Answer contains no more and no less than four significant figures.
Now, for every mole of Al(C9H6NO)3, there is 1 mole of Al^3+. i.e., 1 mole of Al=1 mole of Al(C9H6NO)3
@@0.1248g of Al(C9H6NO)3 *(1 mole/459.4317 g)= moles of Al(C9H6NO)3
moles of Al(C9H6NO)3=moles of Al^3+
moles of Al^3+*(26.98g/1 mole)= mass of Al^3+ in grams
(mass of Al^3+ in grams/1.8571g)*100=mass percent of Al^3+ in the mineral sample
***Answer contains no more and no less than four significant figures.
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