A sample of oxygen at 24.0 degrees celcius and 99.3 kpa was found to have a volume of 455 ml. How many grams of O2 were in the sample?

Answer 1

Use the gas law and do some conversion:

PV=nRT

Where

P=99.3kpa
V=455mL=0.455L
R=0.0821 L·atm/mol·K
T=24.0 C
and
n=???

Convert kpa to atm and C to K

1Atm = 101.325 kPa

So,

99.3 kPa*(1 atm/101.325kPa)= 0.980 atm

K=C + 273

So,

24.0 + 273=297K

Solve for n:

n=PV/RT

n*(32.00g/mole)= O2 in grams

Answer contains three significant figures.

Answer 2

Answer

Answer 3

Answer for the question