Asked by Anonymous
A 200.0g sample of glucose(180.16g/mol, Kmp=1.86 degrees celcius/m, mp=146 degrees celcius)is contaminated with 5.000g of table salt, sodium chloride(58.44g/mol, mp=801 degrees celcius). What would the expected melting point of the mixture be?
Answers
Answered by
DrBob222
I assume NaCl does not ionize when dissolved in glucose.
mols NaCl = grams/molar mass.
Subsittute and solv for mols NaCl.
Then m = molality NaCl = mols/kg solvent
Substitute mols from above and kg solvent is 0.200 kg, and solve for m.
Then delta T = Kf*m
You have Kf for glucose in the problem and you've solved for m, calculate delta T.
Finally, subtract delta T from the normal melting point of glucose.
mols NaCl = grams/molar mass.
Subsittute and solv for mols NaCl.
Then m = molality NaCl = mols/kg solvent
Substitute mols from above and kg solvent is 0.200 kg, and solve for m.
Then delta T = Kf*m
You have Kf for glucose in the problem and you've solved for m, calculate delta T.
Finally, subtract delta T from the normal melting point of glucose.
Answered by
Anonymous
Thanks, DrBob222
Answered by
meg
is the answer 141.67 pleaase help?
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