Question
An MRT Train accelerates at a rate of 2.75 m/s^2 from rest for 3.00 seconds.How fast will the train be moving after that time?
Answers
john
v = V0 + a * t
V0 = 0
a = 2.75 m/s^2
t = 3.00 s
v = 0 + 2.75 * 3.00 m/s
v = 8.25 m/s
V0 = 0
a = 2.75 m/s^2
t = 3.00 s
v = 0 + 2.75 * 3.00 m/s
v = 8.25 m/s