Asked by Lesh
As a train accelerates from a station, it reaches a speed of 4.7m/s in 5.0s. If a train acceleration remains constant what is its speed after an additional 6.0s has elapsed?
Answers
Answered by
drwls
You will have to assume that it started at speed = 0 at t = 0. The acceleration rate is therefore
a = 4.7/5.0 = 0.94 m/s^2
After 6.0 MORE seconds at the same acceleration rate, the speed will be
0.94 * 11 = 10.34 m/s
11 seconds is the total time from the start of motion.
a = 4.7/5.0 = 0.94 m/s^2
After 6.0 MORE seconds at the same acceleration rate, the speed will be
0.94 * 11 = 10.34 m/s
11 seconds is the total time from the start of motion.
Answered by
Lesh
drwls, so where did the 11 come from that you multiplied with 0.94?
Answered by
bobpursley
six seconds is added to the original five seconds, time =11s
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