Asked by Steven
For the curve given by 4x^2+y^2=48+2xy show that ((dy)/(dx))=(y-4x)/(y-x)
Answers
Answered by
bobpursley
take the function, and do the partial..
8x dx + 2y dy = 0 + 2x dy + 2y dx
dx(8x-2y)= dy(2x-2y)
dy/dx= (4x-y)/(x-y)=(y-4x)/(y-x)
8x dx + 2y dy = 0 + 2x dy + 2y dx
dx(8x-2y)= dy(2x-2y)
dy/dx= (4x-y)/(x-y)=(y-4x)/(y-x)
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