Asked by Anon
A curve is such that dy/dx = 2- 8(3x+4)^-1/2
- A point P moves along the curve in such a way that the x-coordinates is increasing at a constant rate of 0.3 units per second. Find the rate of change of the y-coordinates as P crosses at the y-axis.
- A point P moves along the curve in such a way that the x-coordinates is increasing at a constant rate of 0.3 units per second. Find the rate of change of the y-coordinates as P crosses at the y-axis.
Answers
Answered by
Steve
recall that
dy/dt = dy/dx * dx/dt
You have
dx/dt = 0.3
so, plug in x=0
dy/dt = (2 - 8/√4) * 0.3 = -0.6
dy/dt = dy/dx * dx/dt
You have
dx/dt = 0.3
so, plug in x=0
dy/dt = (2 - 8/√4) * 0.3 = -0.6
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