A curve is such that dy/dx = 2- 8(3x+4)^-1/2

Question

- A point P moves along the curve in such a way that the x-coordinates is increasing at a constant rate of 0.3 units per second. Find the rate of change of the y-coordinates as P crosses at the y-axis.

Answer 1

recall that

dy/dt = dy/dx * dx/dt
You have
dx/dt = 0.3
so, plug in x=0

dy/dt = (2 - 8/√4) * 0.3 = -0.6