Asked by jecce.

im curious if i post my work on here will anyone check it for me to see if it is right?
Answered by DrBob222
Sure. One question per post. If you give us the problem and your answer we can give you a yes or no. If you show your work we can tell you where you are going wrong if the answer is wrong.
Answered by jecce.
ok well i had to find the molar mass of these substances.

A) NH3 = 17.00 grams
B) N2H4 = 32.00 grams
C) (NH4)2 Cr2O7 = 776 grams

For the second part i had to find how many moles of compounds are present in 1.00 grams of each substance i found above.

A) i did 1.00g x (1 mole)/(17.00g) and got 5.9x10^-2

B) i did 1.00g x (1 mole)/(32.00g) and got 3.1x10^/2

C) i did 1.00g x (1 mole)/(776g) and got 12.9x10^-4

The second part finding the moles of the compounds confused me. So if you could please check my work and answer and explain why its wrong that would help me a lot.

Thanks!
Answered by jecce.
Sorry HUGE mistake i made....
this is what its suppose to be.

B) i did 1.00g x (1 mole)/(32.00g) and got 3.1x10^-2
Answered by bobpursley
C and C are wrong. The molar mass of ammonium dichromate is about a third of what you used. Recheck that.
Answered by jecce.
can you tell me how to add that?
because what im doing is

(NH4)2 Cr2)7

N= 14.00
H= 4x 1.00 = 4

so..
18.00 x 2 = 36.00

and
Cr= 2x 52 = 104
O= 7X 16 = 112

which equals to 216 and then i add 36 and get 776.
Answered by jecce.
can you tell me how to add that?
because what im doing is

(NH4)2 Cr2O7


*****Sorry for my bad typing!
Answered by bobpursley
Hmmmm. Here in Texas adding 216 plus 36 is considerably less than 776.
Answered by jecce.
whoa.
ha your right its 252!

i must have put that wrong in the calculator!

thanksss!
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