Asked by Ethan
how do i find the inverse of f(x)= (3x+7)/(x-2)
Answers
Answered by
drwls
The subject is spelled precalculus.
Let's call f(x) y, and then express x in terms of y.
y = (3x +7)/(x-2)
xy - 2y = 3x + 7
x(y-3) = 7+2y
x = (7+2y)/(y-3)
Finally, call this the "inverse function of x" by changing variables
f^(-1)(x) = (7+2x)/(x-3)
It is the function which will give you x back if you plug in f(x).
Let's call f(x) y, and then express x in terms of y.
y = (3x +7)/(x-2)
xy - 2y = 3x + 7
x(y-3) = 7+2y
x = (7+2y)/(y-3)
Finally, call this the "inverse function of x" by changing variables
f^(-1)(x) = (7+2x)/(x-3)
It is the function which will give you x back if you plug in f(x).
Answered by
Ethan
Oh sorry, haha thank you for correcting me and thank you for helping me out.
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