Asked by Anonymous
find all the zeros of the equation.
-3x^4+27x^2+1200=0
I'm really confused, can someone help explain?
-3x^4+27x^2+1200=0
I'm really confused, can someone help explain?
Answers
Answered by
Damon
let z = x^2
-3 z^2 + 27 z + 1200 = 0
divide by -3
z^2 - 9 z - 400 = 0
(z-25)(z+16) = 0
z = 25 ---> x = 5 or -5
z = -16 --> x = 4 i or -4i
-3 z^2 + 27 z + 1200 = 0
divide by -3
z^2 - 9 z - 400 = 0
(z-25)(z+16) = 0
z = 25 ---> x = 5 or -5
z = -16 --> x = 4 i or -4i
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