Asked by Anonymous
How to find the zeros of -16t^2 + 200 = 0?
Answers
Answered by
Bosnian
- 16 t ^ 2 + 200 = 0 Subtract 200 to toth sides
- 16 t ^ 2 + 200 - 200 = 0 - 200
- 16 t ^ 2 = - 200 Divide both sides by - 16
- 16 t ^ 2 / - 16 = - 200 / - 16
t ^ 2 = - 200 / -16
t ^ 2 = 200 / 16
t ^ 2 = 4 * 50 / ( 4 * 4 )
t ^ 2 = 50 / 4
t ^ 2 = 2 * 25 / ( 2 * 2 )
t ^ 2 = 25 / 2
t = + OR - sqroot ( 25 / 2 )
t = + OR - sqroot ( 25 ) / sqroot ( 2 )
t = + OR - 5 / sqroot ( 2 )
t1 = 5 / sqroot ( 2 )
t2 = - 5 / sqroot ( 2 )
- 16 t ^ 2 + 200 - 200 = 0 - 200
- 16 t ^ 2 = - 200 Divide both sides by - 16
- 16 t ^ 2 / - 16 = - 200 / - 16
t ^ 2 = - 200 / -16
t ^ 2 = 200 / 16
t ^ 2 = 4 * 50 / ( 4 * 4 )
t ^ 2 = 50 / 4
t ^ 2 = 2 * 25 / ( 2 * 2 )
t ^ 2 = 25 / 2
t = + OR - sqroot ( 25 / 2 )
t = + OR - sqroot ( 25 ) / sqroot ( 2 )
t = + OR - 5 / sqroot ( 2 )
t1 = 5 / sqroot ( 2 )
t2 = - 5 / sqroot ( 2 )
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