Question
It takes 37.16 mL of 0.510 M HCL to neutralize 25.00 mL of NaOh. What is the concentration of the NaOH?
Answers
Steve
there are .03716*0.510 = 0.01895 moles of HCl
Each mole of HCl neutralizes 1 mole of NaOH
So, there were .01895 moles of NaOH in 0.025L of solution. Thus, the solution was
0.01895mol/0.025L = 0.758M
Each mole of HCl neutralizes 1 mole of NaOH
So, there were .01895 moles of NaOH in 0.025L of solution. Thus, the solution was
0.01895mol/0.025L = 0.758M