Asked by Anonymous
it takes a certain gas 1.98 times as long to diffuse as an equal volume of helium under the same conditions. what is the calculated molecular weight of the gas?
Answers
Answered by
bobpursley
Isn't this Graham's law of diffusion
rate1/rate2 = sqrt(mass2)/sqrt(mass1)
1.98= sqrt (mass1/4)
square both sides, multiply both sides by 4.
In my head, it is about 16
rate1/rate2 = sqrt(mass2)/sqrt(mass1)
1.98= sqrt (mass1/4)
square both sides, multiply both sides by 4.
In my head, it is about 16
Answered by
Travolter Mboya
Core of Graham's law of diffusion
r¹/r²=√(M²/M¹ )
2.3=√(M¹/32)
Sq. both sides & multiply both side by 32
My head dictates it 169
r¹/r²=√(M²/M¹ )
2.3=√(M¹/32)
Sq. both sides & multiply both side by 32
My head dictates it 169
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