Asked by Lexie
A 0.327 g sample of a mixture of NaOH(s) and NaCl(s) requires 31.5 mL of 0.150 M HCl(aq) to react with all the NaOH(s). What is the mass percentage of the NaOH(s) in the mixture?
Answers
Answered by
DrBob222
HCl + NaOH ==> NaCl + H2O
mols HCl = M x L = ?
Look at the coefficients in the balanced equation. mols HCl = mols NaOH.
Then g NaOH = mols NaOH x molar mass NaOH = ? This is the theoretical yield.
%yield = (mass NaOH/mass sample)*100 = ?
mols HCl = M x L = ?
Look at the coefficients in the balanced equation. mols HCl = mols NaOH.
Then g NaOH = mols NaOH x molar mass NaOH = ? This is the theoretical yield.
%yield = (mass NaOH/mass sample)*100 = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.