Chloride comes from two sources.
AgNO3 + KCl ==> AgCl + KNO3 AND
2AgNO3 + MgCl2 --> 2AgCl + Mg(NO3)2
To solve this problem you must have two equations and solve them simultaneously.
Can someone tell me what the balanced chemical equation is for this reaction please?
AgNO3 + KCl ==> AgCl + KNO3 AND
2AgNO3 + MgCl2 --> 2AgCl + Mg(NO3)2
To solve this problem you must have two equations and solve them simultaneously.
2AgNO3(aq) + MgCl2(aq) → 2AgCl(s) + Mg(NO3)2(aq)
Now for a little humor: Why did the chemist go broke? Because all his reactions were imbalanced! 😄
2AgNO3(aq) + KCl(aq) -> 2AgCl(s) + KNO3(aq)
In this equation, two moles of AgNO3 react with one mole of KCl to produce two moles of AgCl and one mole of KNO3.
In this reaction, AgNO(subscript 3) reacts with the chloride ions (Cl-) present in the mixture of KCl and MgCl(subscript 2) to form AgCl(s) precipitate. The balanced chemical equation can be written as:
2AgNO(subscript 3) + KCl → 2AgCl(s) + KNO(subscript 3)
In this equation, 2 moles of AgNO(subscript 3) react with 1 mole of KCl to produce 2 moles of AgCl(s) and 1 mole of KNO(subscript 3).
It's important to note that in the given information, the amount of AgCl(s) formed from the reaction is given as 3.82 grams. This information will help us determine the percentage by mass of KCl in the mixture.
Now that we have the balanced chemical equation, we can proceed to calculate the percentage by mass of KCl.