Asked by Lisa
Find the exact value and approximate. 11^ -x+4 = 5^ 3x-2 (-x+4)log11 = (3x-2)log5
Answers
Answered by
Steve
(-x+4)log11 = (3x-2)log5
-log11 x + 4log11 = 3log5 x - 2log5
-(log11+3log5)x = -(2log5 + 4log11)
x = (2log5+4log11)/(log11+3log5)
and, of course, you could go on and say
x = log(5^2*11^4)/log(11*5^3)
= log366025/log1375
or even
log<sub>1375</sub>366025
-log11 x + 4log11 = 3log5 x - 2log5
-(log11+3log5)x = -(2log5 + 4log11)
x = (2log5+4log11)/(log11+3log5)
and, of course, you could go on and say
x = log(5^2*11^4)/log(11*5^3)
= log366025/log1375
or even
log<sub>1375</sub>366025
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.