Asked by Carol
use a calculator to find approximate solutions of the equation. 8.06x^2+25.8726x-25.047256=0
Answers
Answered by
MathMate
For a quadratic equation
Ax²+Bx+C=0
the solutions are
x=(-B±√(B²-4AC))/(2A)
For this question,
A=8.06
B=25.8726
C=-25.047256
You can substitute the values and calculate the approximate values of the roots. They are approximate because of rounding errors, not because of the formula.
You can attempt the next question the same way.
At the end, substitute the value of x that you have found into the original equation to see if it adds up to zero, as it should be.
Ax²+Bx+C=0
the solutions are
x=(-B±√(B²-4AC))/(2A)
For this question,
A=8.06
B=25.8726
C=-25.047256
You can substitute the values and calculate the approximate values of the roots. They are approximate because of rounding errors, not because of the formula.
You can attempt the next question the same way.
At the end, substitute the value of x that you have found into the original equation to see if it adds up to zero, as it should be.
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