well, just remember that
sin = y/r
cos = x/r
sin u cannot be negative if u is in QII.
Anyway, just recall your common triangles: 5-12-13 and 3-4-5. Draw them in the proper quadrant and find the missing side.
Then just plug the numbers into your difference formula for cosine.
Find the exact value of the trig expression given that sin u = -5/13 and cos v = -4/5.
u and v are in the second quadrant.
cos(v - u)
2 answers
Thanks Steve