Asked by anonymous
A repairman purchased several furnace-blower motors for a total cost of $150. If his cost per motor had been $5 less, he could have purchased 1 additional motor. How many motors did he buy at the regular rate?
Answers
Answered by
Don
This is similar to what I just answered earlier.
x = total cost
y= # of motors bought
150 = x*y
solving for y:
150/y= x <--- (1)
now we know:
150=(x-2)*(1+y) <--- (2)
substitute using (2) and (1) we get :
150=((150/y)-5)*(1+y)
30 = y^2+y
y^2+y -30= 0
(y+6)(y-5)=0
y = -6, 5
real solution is 5, can't buy negative engines..
x = total cost
y= # of motors bought
150 = x*y
solving for y:
150/y= x <--- (1)
now we know:
150=(x-2)*(1+y) <--- (2)
substitute using (2) and (1) we get :
150=((150/y)-5)*(1+y)
30 = y^2+y
y^2+y -30= 0
(y+6)(y-5)=0
y = -6, 5
real solution is 5, can't buy negative engines..
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