Asked by jorge
ow many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is 2.70 g/mL? Show all steps of your calculation as well as the final answer. (5 points)
AlCl3 → Al + Cl2
AlCl3 → Al + Cl2
Answers
Answered by
DrBob222
2AlCl3 → 2Al + 3Cl2
mass = volume x density
mass = 78.3 x 2.70 = approx 211 g but you need a more accurate answer than my estimate.
mols Al = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Al to mols AlCl3.
Then g AlCl3 = mols AlCl3 x molar mass AlCl3
mass = volume x density
mass = 78.3 x 2.70 = approx 211 g but you need a more accurate answer than my estimate.
mols Al = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Al to mols AlCl3.
Then g AlCl3 = mols AlCl3 x molar mass AlCl3
Answered by
j
can you do this with the numbers please?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.