Question

ow many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is 2.70 g/mL? Show all steps of your calculation as well as the final answer. (5 points)

AlCl3 → Al + Cl2

Answer 1

2AlCl3 → 2Al + 3Cl2

mass = volume x density
mass = 78.3 x 2.70 = approx 211 g but you need a more accurate answer than my estimate.
mols Al = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Al to mols AlCl3.
Then g AlCl3 = mols AlCl3 x molar mass AlCl3

Answer 2

can you do this with the numbers please?