Asked by Mark

How many grams of cesium chloride (CsCl) will be needed to make 750. mL of a 0.100 M
CsCl aqueous solution? The formula mass of CsCl is 168.36 g/mol.
Remember
Molarity: M = (mol solute) / (L of solution)
I need help solving this problem

Answers

Answered by bobpursley
mass=molarity*volumeinliters*molmass
= .1*.75*168 grams
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