Asked by unk
how many grams of aluminum are in 25.0 ml of a 14%(w/v) solution of Al2O3?
Answers
Answered by
DrBob222
14g Al2O3 w/v means 14g Al2O3/100 ml soln.
14 g Al2O3 x (2*Al/Al2O3 = 14 x (2*27/102) = 7.4 g Al which means 7.4 g Al/100 mL soln. So how much would be in 25.0 mL? Something like 1/4 that? I've estimated my numbers so you need to go through and recalculate everything.
14 g Al2O3 x (2*Al/Al2O3 = 14 x (2*27/102) = 7.4 g Al which means 7.4 g Al/100 mL soln. So how much would be in 25.0 mL? Something like 1/4 that? I've estimated my numbers so you need to go through and recalculate everything.
Answered by
unk
i am not clear? i came up with .074g??
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