Asked by Davis
A firefighter with a mass of 52 kg slides down a vertical pole with an acceleration of 3 m/s/s . The acceleration of gravity is 10 m/s/s. What is the friction force that is acting on him
Answers
Answered by
bobpursley
net force=mass*a
mg-friction=mass*a
friction=mg-ma=m(g-a)
mg-friction=mass*a
friction=mg-ma=m(g-a)
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