A firefighter 41.8m away from a burning building, directs Zach stream of water from a ground level fire hose at an angle of 33.0 degrees above the horizontal . If the speed of the streams it leaves the hose is 42.7m/s, at what height will the stream of water hit the building

Answer 1

Vo = 42.7m/s[33o]
Xo = 42.7*cos33 = 35.81 m/s.
Yo = 42.7*sin33 = 23.26 m/s.

X = Xo * t = 41.8 m.
35.81t = 41.8
t = 1.17 s

h = Yo*t - 4.9*t^2
h = 23.26*1.17 - 4.9*1.17^2 = 20.51 m.