Asked by Megan
(NH4)2CO3 <-> 2NH3 + CO2 + H2O
solid (NH4)2CO3 is placed in an evacuated container at 115C. When equilibrium is reached Kp = 1.93x10^-3. Extra NH3 gas is added, when equilibrium is reestablished, the partial pressure of NH3 is four times the partial pressure of H20. What is the partial pressure of NH3?
solid (NH4)2CO3 is placed in an evacuated container at 115C. When equilibrium is reached Kp = 1.93x10^-3. Extra NH3 gas is added, when equilibrium is reestablished, the partial pressure of NH3 is four times the partial pressure of H20. What is the partial pressure of NH3?
Answers
Answered by
DrBob222
I believe this problem is solved this way.
........(NH4)2CO3 ==> 2NH3 + CO2 + H2O
If H2O is p, then CO2 is p and NH3 is 4p.
Substitute into Kp expression and solve for p and 4p.
........(NH4)2CO3 ==> 2NH3 + CO2 + H2O
If H2O is p, then CO2 is p and NH3 is 4p.
Substitute into Kp expression and solve for p and 4p.
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