Asked by Megan
solid (NH4)2CO3 is placed in an evacuated container at 115C. When equilibrium is reached the total pressure inside the vessel is 0.473 atm. Some solid remain in the vessel at equilibrium. Calculate Kp.
Answers
Answered by
DrBob222
..........(NH4)2CO3 ==> 2NH3 + CO2 + H2O
I..........solid.........0......0.....0
C..........solid........2p......p.....p
E..........solid........2p......p.....p
Kp = p^2NH3 * pCO2 * pH2O
Ptotal = pNH3 + pCO2 + pH2O
0.473 = 2p + p + p = 4p
Solve for p and substitute into Kp expression and solve for Kp.
I..........solid.........0......0.....0
C..........solid........2p......p.....p
E..........solid........2p......p.....p
Kp = p^2NH3 * pCO2 * pH2O
Ptotal = pNH3 + pCO2 + pH2O
0.473 = 2p + p + p = 4p
Solve for p and substitute into Kp expression and solve for Kp.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.