Question

A ball is thrown up on the surface of a moon. Its height above the lunar surface (in feet) after t seconds is given by the formula
h=308t−(14/6t^2)
Find the time that the ball reaches its maximum height.
Answer =
Find the maximal height attained by the ball
Answer =
as usual for quadratics, the vertex is at t = -b/2a = 308/(14/3) = 66

Odd, since g is 1/6 of earth's, I expected the equation to be -16/6 t^2

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