Question
Use the derivative of sinx and cosx to develop the derivatives of y=secx and y=tanx? Help would be much appreciated
Answers
Steve
y = secx
y = (cosx)^-1
y' = -1 (cosx)^-2 (-sinx)
= sinx/cos^2x
= secx tanx
similarly for tanx, using the quotient rule
y = (cosx)^-1
y' = -1 (cosx)^-2 (-sinx)
= sinx/cos^2x
= secx tanx
similarly for tanx, using the quotient rule