Asked by anonymous
The length of the base and the height of a triangle are numerically equal. Their sum is 16 less than the number of units in the area of the triangle. Find the area of the triangle.
Answers
Answered by
Reiny
let the height be x
then the base is x
area of triangle = (1/2)x^2
sum = 2x
2x = (1/2)x^2 - 16
4x = x^2 - 32
x^2 - 4x - 32 = 0
(x-8)(x+4) = 0
x = 8 or x = -4, the latter makes no sense,
so if x=8, area = (1/2)64 = 32
check
is their sum 16 less than the area?
or
is 16 less than 32 by 16 ? , YES
then the base is x
area of triangle = (1/2)x^2
sum = 2x
2x = (1/2)x^2 - 16
4x = x^2 - 32
x^2 - 4x - 32 = 0
(x-8)(x+4) = 0
x = 8 or x = -4, the latter makes no sense,
so if x=8, area = (1/2)64 = 32
check
is their sum 16 less than the area?
or
is 16 less than 32 by 16 ? , YES
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