Asked by Anonymous
WHAT IS THE BASE LENGTH OF AN ISOSCELES TRIANGLE IF YOU KNOW THE EQUAL SIDES HAVE A VALUE OF 5 AND THE ANGLE BETWEEN THEM IS 45 DEGREES AND THE BASE ANGLES ARE 67.5 DEGREES?
Answers
Answered by
Reiny
Why are you shouting?
You could use the Sine Law
let the missing side by x
x/sin45 = 5/sin67.5
x = 5sin45/sin67.5 = 3.827
you could also use the Cosine Law:
x^2 = 5^2 + 5^2 - 2(5)(5)cos45
= 50 - 35.35534
= 14.6447
x = √14.6447 = 3.827
You could use the Sine Law
let the missing side by x
x/sin45 = 5/sin67.5
x = 5sin45/sin67.5 = 3.827
you could also use the Cosine Law:
x^2 = 5^2 + 5^2 - 2(5)(5)cos45
= 50 - 35.35534
= 14.6447
x = √14.6447 = 3.827
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