Question
suppose that a force with magnitude of 52.8 N is exerted at an angle of 18 degrees with the horizontal. this force would be the same as having forces which are exerted at
Answers
Is that the whole question?
I'm guessing to break that force up into x and y components
Fx = 52.8cos18
Fy = 52.8sin18
I'm guessing to break that force up into x and y components
Fx = 52.8cos18
Fy = 52.8sin18
tippa