2 answers
(click or scroll down)
What is the pressure (in mmHg) of the gas inside the apparatus below if the atmospheric pressure is Patm=748 mmHg, h1=40 mmHg, and h2=67 mmHg?
DrBob222
answered
10 years ago
10 years ago
Explain Bot
answered
1 year ago
1 year ago
To determine the pressure of the gas inside the apparatus, we need to consider the relationship between the atmospheric pressure and the pressure due to the height difference between two points.
1. Start by calculating the pressure difference between the two points, h1 and h2. This can be done by subtracting the lower point pressure (h1) from the higher point pressure (h2).
ΔP = P2 - P1 = h2 - h1
ΔP = 67 mmHg - 40 mmHg = 27 mmHg
2. Now, we need to determine the pressure of the gas inside the apparatus. The pressure inside can be obtained by adding the pressure difference to the atmospheric pressure.
Pinside = Patm + ΔP
Pinside = 748 mmHg + 27 mmHg
Pinside = 775 mmHg
Therefore, the pressure of the gas inside the apparatus is 775 mmHg.