Asked by ain
Vector A is 10 unit longs and points at 25 degree above the positive x axis. Another vector B is 8 units long and points along yhe positive x axis. Determine the magnitude of A X B.
Answers
Answered by
Don
If I'm reading this correctly, the question wants you to find the magnitude of vector A and then multiply it to magnitude of vector B. If that's the case then…
Vector A has both an x and y component:
Fx=10cos25=9.06
Fy=10sin25=4.266
Magnitude of A = sqrt(9.06^2+4.266^2)^(1/2) = 3.16
Vector B only has x components:
Fx=8
Magnitude of B = 8
3.16*8 = 25.28
Vector A has both an x and y component:
Fx=10cos25=9.06
Fy=10sin25=4.266
Magnitude of A = sqrt(9.06^2+4.266^2)^(1/2) = 3.16
Vector B only has x components:
Fx=8
Magnitude of B = 8
3.16*8 = 25.28
Answered by
Don
Sorry, I made an error…
Vector A has both an x and y component:
Fx=10cos25=9.06
Fy=10sin25=4.266
Magnitude of A = sqrt(9.06^2+4.266^2) = 10.0141
Vector B only has x components:
Fx=8
Magnitude of B = 8
10.0141*8 = 80.112
Vector A has both an x and y component:
Fx=10cos25=9.06
Fy=10sin25=4.266
Magnitude of A = sqrt(9.06^2+4.266^2) = 10.0141
Vector B only has x components:
Fx=8
Magnitude of B = 8
10.0141*8 = 80.112
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