Question
How do you find the unit vector in the direction of the given vector in w = 7i − 3j. can someone explain it for me, i really don't know!
Answers
Damon
what is the magnitude of that vector?
sqrt (49 + 9) = sqrt 58
so
(1/sqrt 58) (7i - 3 j)
= (7/sqrt 58) i - (3/sqrt 58) j
the magnitude of that vector will be one
49/58 + 9/58 :)
sqrt (49 + 9) = sqrt 58
so
(1/sqrt 58) (7i - 3 j)
= (7/sqrt 58) i - (3/sqrt 58) j
the magnitude of that vector will be one
49/58 + 9/58 :)
anonymous
thanks damon