Question

given the thermochemical equations,
B2O3 + 3H2O -> 3O2 + B2H6 delta h = -2035 kj
H2O -> H2O delta h = 44 kj
H2 + 1/2O2 -> H2O delta h = -286 kj
2B + 3H2 -> B2H6 delta h = 36 kj
what is the delta hf for 4B + 3O2 -> 2B2O3?
You have omitted the phases. Rather than guess what they are I would rather you posted them.

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