Asked by tal
Given the thermochemical equation:
2 Al(s) + 3/2 O2(g) > Al2O3(s) ΔH = -95.7 kJ
find the heat of reaction, ΔH, for the following reaction:
2 Al2O3(s)> 4 Al(s) + 3 O2(g)
Select one:
a. -95.7 kJ
b. +95.7 kJ
c. -47.8 kJ
d. +47.8 kJ
e. +191.4 kJ
2 Al(s) + 3/2 O2(g) > Al2O3(s) ΔH = -95.7 kJ
find the heat of reaction, ΔH, for the following reaction:
2 Al2O3(s)> 4 Al(s) + 3 O2(g)
Select one:
a. -95.7 kJ
b. +95.7 kJ
c. -47.8 kJ
d. +47.8 kJ
e. +191.4 kJ
Answers
Answered by
DrBob222
You have the reaction as shown. You want the reverse reaction and double that. So take dH that you have, change the sign (because of the reversal) and double it.
Answered by
tal
would it be a positive or a negative though?
Answered by
tal
it would be e...
Answered by
DrBob222
yes.
You reversed the sign because the reaction is reversed. So that makes it positive. Then double that for e.
You reversed the sign because the reaction is reversed. So that makes it positive. Then double that for e.
Answered by
tal
thank you !!!
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