Question

find real solutions
sq.root 2x+5 - sq.root x+6 = 1

Answer 1

(2x+5)^.5 - (x+6)^.5 = 1 you mean maybe, parentheses missing if so

(2x+5)^.5 = 1 +(x+6)^.5

2x+5 = 1 + 2 (x+6)^.5 + x+6

(x - 2) = 2 (x+6)^.5

x^2 - 4 x + 4 = 4 x + 24

x^2 - 8 x - 20 = 0

(x-10)(x+2) = 0

x = 10 or x = -2
go back and see what works in the original now.

Answer 2

yes thank you!