Question

Find the real solutions of the equation:

14x^2 - 5x^2 - 1 = 0

I know that you have to use au^2 + bu +c = 0

so u^2 - 5x -1 which is prime.
So would the answer be that the solution is the empty set?

Answer 1

Hmmm. is the second term x^2 or not?

14x^2-5x^2=7x^2

x^2=1/7
x= +-sqrt (1/7)