Question
Find the real solutions of each equation.
1) 1 / (x+6)^2 = 1 / (x+6) + 12
2) 8x^2/3 - 39x^1/3 - 5 = 0
I have no idea how to do these. Please help!!! Thank you!
1) 1 / (x+6)^2 = 1 / (x+6) + 12
2) 8x^2/3 - 39x^1/3 - 5 = 0
I have no idea how to do these. Please help!!! Thank you!
Answers
MathMate
1.
Multiply both sides by (x+6)^2 to get
1-(x+6)-12(x+6)²=0
Expand and solve for x.
2. Substitute y=x^(1/3) and solve for the resulting quadratic in y.
Multiply both sides by (x+6)^2 to get
1-(x+6)-12(x+6)²=0
Expand and solve for x.
2. Substitute y=x^(1/3) and solve for the resulting quadratic in y.