Asked by Iworlock
Iam looking for the entire formula on how to solve this.
If a person on a 35.0 m diameter Ferris wheel feels 30% heavier at the bottom of the wheel, how fast is it going around?
Is N/Mg = 1 + v^2/Rg actual weight
If a person on a 35.0 m diameter Ferris wheel feels 30% heavier at the bottom of the wheel, how fast is it going around?
Is N/Mg = 1 + v^2/Rg actual weight
Answers
Answered by
bobpursley
mv^2/R * m + mg=1.30mg
.3gR=v^2
.3gR=v^2
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