Asked by Aoi
This is the entire question:
A curve has the equation y=(x+2)√(x-1).
i)Show that dy/dx = kx/√(x-1) and find k
ii)Hence, evaluate limit 2 to 5
∫ kx/√(x-1)dx
My answer: first part, i have already shown, and k is equals to 3/2
I don't get the second part though, it says evaluate ∫ kx/√(x-1)dx, isnt that equals to ∫ (dy/dx) dx, which is equals to y? o.o
A curve has the equation y=(x+2)√(x-1).
i)Show that dy/dx = kx/√(x-1) and find k
ii)Hence, evaluate limit 2 to 5
∫ kx/√(x-1)dx
My answer: first part, i have already shown, and k is equals to 3/2
I don't get the second part though, it says evaluate ∫ kx/√(x-1)dx, isnt that equals to ∫ (dy/dx) dx, which is equals to y? o.o
Answers
Answered by
bobpursley
correct. Evaluate y(5)-y(2)
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