-3* cube root of 2 is a negative number, so your result has to stay negative.
change it to
- cuberoot(54)
What is the entire radial form of -3* cube root of 2?
I go cube root of 54 as my answer but it is wrong
5 answers
isn't negative not supposed to go inside the cube root
I have one more question
I tried this question but got the wrong answer...
3-x= √x^2-5
(The square root is over whole x^2-5)
My answer was x=2/3
I tried this question but got the wrong answer...
3-x= √x^2-5
(The square root is over whole x^2-5)
My answer was x=2/3
squaring ... 9 - 6x + x² = x² - 5
x = 7/3
x = 7/3
yes -∛54 = ∛-54
Did you try your answer for the other one??
(2/3)^2-5 is negative.
so its square root is not real
3-x = √(x^2-5)
9-6x+x^2 = x^2-5
6x = 14
x = 7/3
Let's try 7/3
3 - 7/3 = 2/3
√(49/9-5) = √4/9 = 2/3
Check the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D3-x,+y%3D%E2%88%9A(x%5E2-5)
Did you try your answer for the other one??
(2/3)^2-5 is negative.
so its square root is not real
3-x = √(x^2-5)
9-6x+x^2 = x^2-5
6x = 14
x = 7/3
Let's try 7/3
3 - 7/3 = 2/3
√(49/9-5) = √4/9 = 2/3
Check the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D3-x,+y%3D%E2%88%9A(x%5E2-5)
0 answers