Question
A ball is launched horizontally at 5 m/s from the top of a 45 m tall building. A man stands at rest 6 m from the base of the building. If there is a 0.3 s reaction time for the man to start moving once he sees the ball launched, find the magnitude of the man's acceleration needed to catch the ball?
Answers
first vertical problem
45 = 4.9 t^2
t = 3.03 seconds to fall
distance ball is from building = 3.03*5
= 15.15
distance man must run = 15.15 - 6 = 9.15
time man has = 3.03-.3 = 2.73 seconds
9.15 = .5 a (2.73)^2
solve for a
45 = 4.9 t^2
t = 3.03 seconds to fall
distance ball is from building = 3.03*5
= 15.15
distance man must run = 15.15 - 6 = 9.15
time man has = 3.03-.3 = 2.73 seconds
9.15 = .5 a (2.73)^2
solve for a
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