Asked by Jennifer
You throw a ball horizontally off of a building with a horizontal velocity of 5 m/s. What's the ball horizontal velocity 8 seconds later? How high should the building be if you want the ball to fall for a total of 12 seconds?
Answers
Answered by
bobpursley
The horizontal velocity is constant.
h=1/2 g 12^2= 1/2 *9.8*144 meters.
h=1/2 g 12^2= 1/2 *9.8*144 meters.
Answered by
dfaerfer
aregergerger
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