You throw a ball into the air with an initial vertical velocity of 31 feet per second. The ball leaves your hand when it is 6 feet above the ground. You catch the ball when it reaches a height of 4 feet. After how many seconds do you catch the ball?

asked by Anonymous

10 years ago

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1 answer

solve for t in

6 + 31t - 16t^2 = 4
t = 2

answered by Steve

2

1

Question

You throw a ball into the air with an initial vertical velocity of 31 feet per second. The ball leaves your hand when it is 6 feet above the ground. You catch the ball when it reaches a height of 4 feet. After how many seconds do you catch the ball?

1 answer

solve for t in

6 + 31t - 16t^2 = 4
t = 2

Steve · Accepted Answer

solve for t in 6 + 31t - 16t^2 = 4 t = 2