Question
You throw a ball into the air with an initial vertical velocity of 31 feet per second. The ball leaves your hand when it is 6 feet above the ground. You catch the ball when it reaches a height of 4 feet. After how many seconds do you catch the ball?
Answers
Steve
solve for t in
6 + 31t - 16t^2 = 4
t = 2
6 + 31t - 16t^2 = 4
t = 2