Asked by Anonymous
You throw a ball into the air with an initial vertical velocity of 31 feet per second. The ball leaves your hand when it is 6 feet above the ground. You catch the ball when it reaches a height of 4 feet. After how many seconds do you catch the ball?
Answers
Answered by
Steve
solve for t in
6 + 31t - 16t^2 = 4
t = 2
6 + 31t - 16t^2 = 4
t = 2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.