Asked by Anonymous

A robot probe drops a camera off the rim of a 387 m high cliff on Mars, where the free-fall acceleration is 3.7 m/s2 .
Find the velocity with which it hits the ground.
Answer in units of m/s
Answered by Henry
V^2 = Vo^2 + 2g*h

Vo = 0
g = 3.7 m/s^2
h = 387 m.
Solve for V

Answered by Lyla
2863.8
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