Asked by Anonymous

A robot probe drops a camera off the rim of
a 437 m high cliff on Mars, where the free-fall
acceleration is 3.7 m/s
2
.
Find the velocity with which it hits the
ground.
Answer in units of m/s
Answered by bobpursley
vf^2=2*a*h
Answered by Anonymous
tried that...
vf^2=2*3.7*437
vf^2=3233.8
vf=56.86651036

but my teacher says its the wrong answer....
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